php打开其他网站获取状态码

php打开其他网站获取状态码？

php获取http状态码程序代码

经常需要判断文件是否可以访问，可以通过http状态码判别，200为正常访问，404为找不到该页面，代码如下

<?php // 设置url $url = 'http://www.111cn.net'; function get_http_status_code($url) {  if(empty($url)) return false;  $url = parse_url($url);  $host = isset($url['host']) ? $url['host'] : '';  $port = isset($url['port']) ? $url['port'] : '80';  $path = isset($url['path']) ? $url['path'] : '';  $query = isset($url['query']) ? $url['query'] : '';  $request = "HEAD $path?$query HTTP/1.1rn"            ."Host: $hostrn"            ."Connection: closern"            ."rn";  $address = gethostbyname($host);  $socket = socket_create(AF_INET, SOCK_STREAM, SOL_TCP);  socket_connect($socket, $address, $port);  socket_write($socket, $request, strlen($request));  $response = split(' ', socket_read($socket, 1024));  socket_close($socket);  return  trim($response[1]); } echo get_http_status_code($url);